(a) 2x 3y = 12(i) and x y = 1(ii) (ii)×3 ==> 3x 3y = 3(iii) Now we can eliminate y by adding (i) & (iii) (i) (iii) ==> 5x = 15 so x=3Algebra Solve by Addition/Elimination xy=9 , 5x2y=32 x y = −9 x y = 9 , 5x − 2y = 32 5 x 2 y = 32 Multiply each equation by the value that makes the coefficients of y y opposite (2)⋅(x y) = (2)(−9) ( 2) ⋅ ( x y) = ( 2) ( 9) 5x−2y = 32 5 x 2 y = 32 SimplifyClick here👆to get an answer to your question ️ Solve the equation by substitution method 2x 3y = 9 , 3x 4y = 5
Solve By The Elimination Meth See How To Solve It At Qanda
